利用1H-磁共振谱计算环化丁苯橡胶的环化度和溶剂参与量

王朝阳　 黄学品　 杨继华　

摘　要：对环化丁苯橡胶的1H-核磁共振谱进行了归属分析，并推导出计算环化度和溶剂参与量的公式。设环化丁苯橡胶的1H-核磁共振谱图中化学位移为 7．0，5．4，4．9 和 3．0～0 处的峰强度分别为 A，B，C 和 D，则环化丁苯橡胶中丁二烯总物质的量(X)＝(B＋C＋D－2A)／7．1，未环化的丁二烯物质的量(Y)＝B／2＋C／4，参与反应的二甲苯物质的量(Z)＝(17．5A－B－C－D)／46．5，环化度(P)＝1－Y／X，溶剂参与量(W)＝91．6Z／X。
关键词：环化丁苯橡胶；1H-核磁共振；环化度；溶剂参与量
分类号：TQ333．99　文献标识码：A
文章编号：1000-890X(2000)05-0263-04

Calculation of cyclization degree and incorporated solvent content of cyclized SBR by 1H-NMR

WANG Chao-yang ,HUANG Xue-pin
(South China University of Technology,Guangzhou 510641)
YANG Ji-hua
(Changchun Institute of Applied Chemistry,Changchtm 130022)

Abstract：1H-NMR spectra of cyclized SBR was analysed and the equations to calculate the cyclization degree and the incorporated solvent content by 1H-NMR method were derived. The total butadiene content in cyclized SBR (x)=(B + C + D - 2A)/7.1, the uncyclized butadiene content (Y) = B/2 + C/4 , the incorporated dimethyl benzene content (Z) = (17.5A - B - C - D )/46.5, the cyclization degree (P) = 1- Y/X and the incorporated solvent content(W) = 91.6Z/X, if the peak densities at the 7.0, 5.4, 4.9 and 3.0～0 chemical shifts in 1H-NMR spectra of cyclized SBR were A, B, C and D respectively.
Keywords：cyclized SBR;1H-NMR;cyclization degree;incorporated solvent content